The bit sequence 10011100 is serially entered (right-most bit first) into an 8-bit parallel out shift register that is initially clear. What are the Q outputs after four clock pulses?a.11110000b.00001100c.10011100d.11000000Clear my choice

The bit sequence 10011100 is entered serially into an 8-bit parallel out shift register. This means that the right-most bit (also known as the least significant bit) is entered first. The shift register is initially clear, which means all its bits are set to 0.

Here's how the bits are shifted after each clock pulse:

1st pulse: 00000001 (The right-most bit, 0, is entered)

2nd pulse: 00000010 (The second bit from the right, 0, is entered. All bits are shifted one place to the left)

3rd pulse: 00000100 (The third bit from the right, 1, is entered. All bits are shifted one place to the left)

4th pulse: 00001001 (The fourth bit from the right, 1, is entered. All bits are shifted one place to the left)

So, after four clock pulses, the Q outputs of the shift register are 00001001. This option is not listed in your choices. Please check the question or the choices again.