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What is the output of the following code? double[] myList = {1, 5, 5, 5, 5, 1}; double max = myList[0]; int indexOfMax = 0; for (int i = 1; i < myList.length; i++) {   if (myList[i] > max) {     max = myList[i];     indexOfMax = i;   } } System.out.println(indexOfMax);  Group of answer choices01234

Question

What is the output of the following code? double[] myList = {1, 5, 5, 5, 5, 1}; double max = myList[0]; int indexOfMax = 0; for (int i = 1; i < myList.length; i++) {   if (myList[i] > max) {     max = myList[i];     indexOfMax = i;   } } System.out.println(indexOfMax);  Group of answer choices01234

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Solution

The output of the code will be 1.

Here's the step by step explanation:

  1. The code initializes an array myList with the elements {1, 5, 5, 5, 5, 1}.

  2. It then sets a variable max to the first element of the array (which is 1) and indexOfMax to 0 (the index of the first element).

  3. The code then enters a for loop which starts from the second element of the array (since it starts from i = 1) and goes up to the last element of the array (i < myList.length).

  4. Inside the loop, it checks if the current element of the array is greater than max. If it is, it updates max to the current element and indexOfMax to the current index.

  5. Since the array has the number 5 from the second to the fifth position, when the loop reaches the second position (i = 1), it updates max to 5 and indexOfMax to 1.

  6. For the rest of the loop, since all other numbers are either 5 or less, max remains 5 and indexOfMax remains 1.

  7. Finally, it prints indexOfMax, which is 1. So, the output of the code is 1.

This problem has been solved

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