In our derivation of the wave equation, we assume the string undergoes small amplitude, longitudinal (along the length of the string) deflections.Group of answer choicesTrueFalse

The linear density of a vibrating string is 10−4kg/m. A transverse wave is propagating on the string, which is described by the equation y = 0.02 sin (x + 30 t), where x and y are in meters and time t in seconds. Then tension in the string is

what happens when single loop is formed of a stationary wave in a stretched string

Transverse waves with a speed of 46.5 m/s are to be produced on a stretched string. A 4.30-m length of string with a total mass of 0.0600 kg is used.(a) What is the required tension in the string? N(b) Calculate the wave speed in the string if the tension is 8.00 N. m/s

A string has a mass of 12.1g. The string is stretched with a force of 89.1 N, giving it length of 18.7 m. Then, the string vibrates transversely at precisely the frequency that corresponds to its fourth normal mode; that is at its fourth harmonic. What is the wavelength of the standing wave created in the string and what is the frequency in the standing wave

Imagine a sinusoidal wave like that of Fig. 16-1b traveling in the positivedirection of an x axis. As the wave sweeps through succeeding elements (that is,very short sections) of the string, the elements oscillate parallel to the y axis. Attime t, the displacement y of the element located at position x is given byy(x, t)
ym sin(kx  vt). (16-2)Because this equation is written in terms of position x, it can be used to find thedisplacements of all the elements of the string as a function of time. Thus, it cantell us the shape of the wave at any given time and how that shape changes as thewave moves along the string.The names of the quantities in Eq. 16-2 are displayed in Fig. 16-3 and de-fined next. Before we discuss them, however, let us examine Fig. 16-4, whichshows five “snapshots” of a sinusoidal wave traveling in the positive directionof an x axis. The movement of the wave is indicated by the rightward progressof the short arrow pointing to a high point of the wave. From snapshot to snap-shot, the short arrow moves to the right with the wave shape, but the stringmoves only parallel to the y axis. To see that, let us follow the motion of the red-dyed string element at x
0. In the first snapshot (Fig. 16-4a), this element is atdisplacement y
0. In the next snapshot, it is at its extreme downward dis-placement because a valley (or extreme low point) of the wave is passingthrough it. It then moves back up through y
0. In the fourth snapshot, it is atits extreme upward displacement because a peak (or extreme high point) of thewave is passing through it. In the fifth snapshot, it is again at y
0, having com-pleted one full oscillation