Select the correct answerWhat will be the output of the following Java code?class Code{ Code()throws IOException { } }class Tantra extends Code{ Tantra() { } public static void main(String[]args) { }}Optionscompile and runs finerun time errorcompile time errorunreported exception java.io.IOException in default constructor
Question
Select the correct answerWhat will be the output of the following Java code?class Code{ Code()throws IOException { } }class Tantra extends Code{ Tantra() { } public static void main(String[]args) { }}Optionscompile and runs finerun time errorcompile time errorunreported exception java.io.IOException in default constructor
Solution
The correct answer is "unreported exception java.io.IOException in default constructor".
Here's why:
In Java, checked exceptions like IOException must be either caught or declared in the method signature using the 'throws' keyword. In the given code, the superclass 'Code' constructor throws an IOException.
When the subclass 'Tantra' extends 'Code', it implicitly calls the superclass constructor. Since the superclass constructor throws a checked exception, the subclass constructor must either catch this exception or declare it in its method signature.
However, in the given code, the subclass constructor does not do either of these. Therefore, a compile-time error occurs, stating that there is an unreported exception java.io.IOException in the default constructor.
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