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sin12∘sin24∘sin48∘sin84∘=cos20∘cos40∘cos60∘cos80∘sin20∘sin40∘sin60∘sin80∘315None of these

Question

sin12∘sin24∘sin48∘sin84∘=cos20∘cos40∘cos60∘cos80∘sin20∘sin40∘sin60∘sin80∘315None of these

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Solution

The given expression is a trigonometric identity.

Let's simplify it step by step:

sin12∘sin24∘sin48∘sin84∘=cos20∘cos40∘cos60∘cos80∘sin20∘sin40∘sin60∘sin80∘

We know that sin(90 - θ) = cosθ and cos(90 - θ) = sinθ.

So, we can rewrite the expression as:

sin12∘sin24∘sin48∘sin84∘ = sin(90 - 20)∘sin(90 - 40)∘sin(90 - 60)∘sin(90 - 80)∘sin20∘sin40∘sin60∘sin80∘

This simplifies to:

sin12∘sin24∘sin48∘sin84∘ = sin70∘sin50∘sin30∘sin10∘sin20∘sin40∘sin60∘sin80∘

We can see that the terms on both sides of the equation are the same, but in a different order.

Therefore, the given expression is true. So, the answer is None of these.

This problem has been solved

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