sin12∘sin24∘sin48∘sin84∘=cos20∘cos40∘cos60∘cos80∘sin20∘sin40∘sin60∘sin80∘315None of these
Question
sin12∘sin24∘sin48∘sin84∘=cos20∘cos40∘cos60∘cos80∘sin20∘sin40∘sin60∘sin80∘315None of these
Solution
The given expression is a trigonometric identity.
Let's simplify it step by step:
sin12∘sin24∘sin48∘sin84∘=cos20∘cos40∘cos60∘cos80∘sin20∘sin40∘sin60∘sin80∘
We know that sin(90 - θ) = cosθ and cos(90 - θ) = sinθ.
So, we can rewrite the expression as:
sin12∘sin24∘sin48∘sin84∘ = sin(90 - 20)∘sin(90 - 40)∘sin(90 - 60)∘sin(90 - 80)∘sin20∘sin40∘sin60∘sin80∘
This simplifies to:
sin12∘sin24∘sin48∘sin84∘ = sin70∘sin50∘sin30∘sin10∘sin20∘sin40∘sin60∘sin80∘
We can see that the terms on both sides of the equation are the same, but in a different order.
Therefore, the given expression is true. So, the answer is None of these.
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