The sum of ages of 5 children born at three year interval each is 50.How old is the youngest child?

Question

The sum of ages of 5 children born at three year interval each is 50.How old is the youngest child?

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Solution 1

Let's denote the age of the youngest child as X.

Since the children are born at three-year intervals, the ages of the other children would be X+3, X+6, X+9, and X+12.

According to the problem, the sum of their ages is 50. So we can set up the following equation:

X + (X+3) + (X+6) + (X+9) + (X+12) = 50

Solving this equation will give us the age of the youngest child.

First, combine like terms:

5X + 30 = 50

Then, subtract 30 from both sides of the equation:

5X = 20

Finally, divide both

This problem has been solved

Solution 2

Let's denote the age of the youngest child as x.

Since the children are born at three-year intervals, the ages of the other children would be x+3, x+6, x+9, and x+12.

According to the problem, the sum of their ages is 50. So we can write the equation as:

x + (x+3) + (x+6) + (x+9) + (x+12) = 50

By simplifying the equation, we get:

5x + 30 = 50

Subtract 30 from both sides:

5x = 20

Finally, divide both sides by 5 to solve for x:

x = 4

So, the youngest child is 4 years old.

This problem has been solved

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