he numbering system which uses base-2 is called the binary system. In binary system (or the base-2 system), a total of 2 digits (0 and 1) are used to represent a number of any size (magnitude).For example, Zero is represented as 0, where0 = (0 * 20) = (0 * 1)Similarly, One (1) is represented as:1 = (1 * 20) = (1 * 1)Now, let us try to represent the following numbers in binary format:Two (2): Since 0 or 1 are the only digits that can be used to represent 2, let us divide 2 by 2 and write the quotient and remainder as follows:[quotient][remainder], i.e.: [1][0]2 = (1 * 21) + (0 * 20) = (2) + (0)Three (3): Since 0 or 1 are the only digits that can be used to represent 3, let us divide 3 by 2 and write the quotient and remainder as follows:[quotient][remainder], i.e.: [1][1]3 = (1 * 21) + (1 * 20) = (2) + (1)Four (4): Since 0 and 1 can be only be used to represent 4, let us divide 4 by 2 and write the quotient and remainder as follows:[quotient][remainder], i.e.: [2][0]. By repeating the above logic for 2 (whose value we already know to be [1][0]) we get [1][0][0]4 = (1 * 22) + (0 * 21) + (0 * 20)4 = (4) + (0) + (0)Fourteen (14): Since only 0 and 1 should be used, let us divide 14 by 2 and write the quotient and remainder as follows:[quotient][remainder], i.e.: [7][0], by repeating the above logic for 7 (7 = [3][1], and 3 = [1][1]) we finally get [1][1][1][0]14 = (1 * 23) + (1 * 22) + (1 * 21) + (0 * 20)14 = (8) + (4) + (2) + (0)Hundred and Fourteen (114): let us divide 114 by 2 and write the quotient and remainder as follows:[quotient][remainder], i.e.: [57][0], by repeating the above logic for 57 (57 = [28][1], 28 = [14][0], 14 = [1][1][1][0]), we finally get [1][1][1][0][0][1][0]114 = (1 * 26) +(1 * 25) +(1 * 24) +(0 * 23) + (0 * 22) + (1 * 21) + (0 * 20)114 = (64) + (32) + (16) + (0) + (0) + (2) + (0)Click on Live Demo to understand the conversion of decimal number system to binary number system.In C, binary numerals are prefixed with a leading 0b (or 0B) (digit zero followed by char 'b'). For example, to store an binary value of four into a variable binary_four, we writeint binary_four = 0b100;Click on Live Demo to understand the conversion of binary number system to decimal number system.Select the correct statements from the given statements.In binary system, decimal 10 is represented as (1 * 101)In binary system, decimal 100 = binary 1100100In binary system, decimal 10 = binary 1010In binary system, decimal 200 = binary 100100
Question
he numbering system which uses base-2 is called the binary system. In binary system (or the base-2 system), a total of 2 digits (0 and 1) are used to represent a number of any size (magnitude).For example, Zero is represented as 0, where0 = (0 * 20) = (0 * 1)Similarly, One (1) is represented as:1 = (1 * 20) = (1 * 1)Now, let us try to represent the following numbers in binary format:Two (2): Since 0 or 1 are the only digits that can be used to represent 2, let us divide 2 by 2 and write the quotient and remainder as follows:[quotient][remainder], i.e.: [1][0]2 = (1 * 21) + (0 * 20) = (2) + (0)Three (3): Since 0 or 1 are the only digits that can be used to represent 3, let us divide 3 by 2 and write the quotient and remainder as follows:[quotient][remainder], i.e.: [1][1]3 = (1 * 21) + (1 * 20) = (2) + (1)Four (4): Since 0 and 1 can be only be used to represent 4, let us divide 4 by 2 and write the quotient and remainder as follows:[quotient][remainder], i.e.: [2][0]. By repeating the above logic for 2 (whose value we already know to be [1][0]) we get [1][0][0]4 = (1 * 22) + (0 * 21) + (0 * 20)4 = (4) + (0) + (0)Fourteen (14): Since only 0 and 1 should be used, let us divide 14 by 2 and write the quotient and remainder as follows:[quotient][remainder], i.e.: [7][0], by repeating the above logic for 7 (7 = [3][1], and 3 = [1][1]) we finally get [1][1][1][0]14 = (1 * 23) + (1 * 22) + (1 * 21) + (0 * 20)14 = (8) + (4) + (2) + (0)Hundred and Fourteen (114): let us divide 114 by 2 and write the quotient and remainder as follows:[quotient][remainder], i.e.: [57][0], by repeating the above logic for 57 (57 = [28][1], 28 = [14][0], 14 = [1][1][1][0]), we finally get [1][1][1][0][0][1][0]114 = (1 * 26) +(1 * 25) +(1 * 24) +(0 * 23) + (0 * 22) + (1 * 21) + (0 * 20)114 = (64) + (32) + (16) + (0) + (0) + (2) + (0)Click on Live Demo to understand the conversion of decimal number system to binary number system.In C, binary numerals are prefixed with a leading 0b (or 0B) (digit zero followed by char 'b'). For example, to store an binary value of four into a variable binary_four, we writeint binary_four = 0b100;Click on Live Demo to understand the conversion of binary number system to decimal number system.Select the correct statements from the given statements.In binary system, decimal 10 is represented as (1 * 101)In binary system, decimal 100 = binary 1100100In binary system, decimal 10 = binary 1010In binary system, decimal 200 = binary 100100
Solution
The correct statements from the given options are:
- In binary system, decimal 10 = binary 1010
- In binary system, decimal 100 = binary 1100100
The first statement is incorrect because decimal 10 is represented as binary 1010, not (1 * 101). The last statement is also incorrect because decimal 200 is represented as binary 11001000, not 100100.
Similar Questions
The number system that uses base-2 is called binary number system while the number system that uses base-8 is called octal number system.In binary system (or base-2 number system,) a total of 2 digits (0 and 1) are used to represent a number of any size (magnitude), whereas in octal system (or base-8 number system,) a total of 8 digits (0, 1, 2, 3, 4, 5, 6 and 7) are used to represent a number of any size (magnitude).The largest digit in octal system is (7)8. Number (7)8 in binary is represented as (111)2. In binary system, three binary digits (bits) are being used to represent the highest octal digit.While converting an octal number to a binary number, three bits are used to represent each octal digit.The following table shows the conversion of each octal digit into its corresponding binary digits.Octal 0 1 2 3 4 5 6 7Binary 000 001 010 011 100 101 110 111For example, an octal number 0246 is converted to its corresponding binary form asOctal Number -> 2 4 6Binary Number -> 010 100 110Hence, 0246 is (010100110)2.Click on Live Demo to understand the conversion of octal number to its corresponding binary number.Similarly, while converting a binary number into its octal form, the binary number is divided into groups of 3 digits each, starting from the exterme right side of the given number . Each of the three binary digits are replaced with their corresponding octal digits.If the group of binary digits to the extreme left side of the number do not have three digits, the required number of zeros are added as a prefix to get three binary digits.For example, let us try and convert a binary number 1101100 into its corresponding octal number.Binary Number -> 1 101 100Binary Number -> 001 101 100 // After prefixing zeros on the extreme left side of the groupOctal Number -> 1 5 4Hence, the octal equivalent of the given binary 1101100 is 0154Click on Live Demo to understand the conversion of a binary number to its corresponding octal form.Select all the correct statements from the given statements.(369)8 is an octal number.Each octal digit is represented using three bits.Binary number (10101010)2 is equivalent to the octal number (252)8.An octal number (364)8 is equivalent to the binary number (011110100)2.
The binary number system is used both in mathematics and digital electronics.The binary number system or base-2 numeral system represents numeric values using only two symbols - 0 (zero) and 1 (one).Computers have circuits (logic gates) which can be in either of the two states: off or on. These two states are represented by 0 (zero) and 1 (one) respectively .It is for this reason that computation in systems is performed using a binary number system (base-2) where all numbers are represented using 0's and 1's.Each binary digit, i.e.,0 (zero) or 1 (one) is called a bit (binary digit). A collection of 8 such bits is called a Byte.In computer terminology, different names have been given to multiples of 210 (i.e., 1024 times existing value), as shown in the table given below:1 byte = 8 bits1 kilobyte = 1024 bytes1 megabyte = 1024 kilobytes1 gigabyte = 1024 megabytes1 terabyte = 1024 gigabytes1 petabyte = 1024 terabytesIn a computer, text, images, music, videos or any type of data for that matter is eventually stored in binary format on the disk.Select the correct statements from the given statements.In binary system the base is 2.A byte is composed of 10 bits.1MB (megabyte) = 8388608 bits.A decimal number cannot be represented as a binary number.
In a base n number system, all numbers are written using only the digits {0,1,..,n−1}. For example, in the decimal (= base 10) number system that you are used to using, all numbers are written using the digits 0,1,..,9, whereas in the binary (= base 2) number system that your computer uses, all numbers are written using the digits 0 and 1 only.Write a function basenum(num, base) that takes as arguments num (a non-negative integer) and base (a non-negative integer not greater than 10), and returns True if all digits of num are strictly less than base and False otherwise (using lazy evaluation). Once again, expect to be tripped up by the first hidden test if you do not use lazy evaluation.For example:>>> basenum(12345, 2)False>>> basenum(12345, 8)True>>> basenum(10110, 2)True>>> basenum(9, 5)False
The binary number system is also known as the base-2 system.a.TRUEb.FALSE
The numbering system which uses base-8 is called octal system. A base (also called radix) is the number of unique digits or symbols (including 0) that are used to represent a given number.In octal system (or the base-8 system), a total of 8 digits (0, 1, 2, 3, 4, 5, 6 and 7) are used to represent a number of any size (magnitude).For example, Zero is represented as 0, where0 = (0 * 80) = (0 * 1)Similarly the numbers 1 One (1), 2 and 7 are represented as follows: :1 = (1 * 80) = (1 * 1)2 = (2 * 80) = (2 * 1)...7 = (7 * 80) = (7 * 1)Now, let us try to represent the following numbers in octal system:Eighteen (18): Since 0 to 7 are the only digits that can be used to represent 18, let us divide 18 by 8 and write the quotient and remainder as follows:[quotient][remainder], i.e.: [2][2]18 = (2 * 81) + (2 * 80) = (16) + (2)Four Hundred and Twenty One (421): Since 0 to 7 are the only digits that can be used to represent 421,, let us divide it by 8 and write the quotient and remainder as follows:[quotient][remainder], i.e.: [52] [5] (further dividing 52 by 8 we get [6][4]), which is [6][4][5]421 = (6 * 82) + (4 * 81) + (5 * 80) = (384) + (32) + (5)Click on Live Demo to understand the conversion of decimal number system to octal number system.In order to differentiate from decimal numbers, octal numerals are prefixed with a leading 0 (zero).For example, to store an octal value of seven into a variable number_seven, we writeint number_seven = 07;Similarly, if we want to store an octal representation of a decimal number 9 in a variable number_nine, we writeint number_nine = 011;Click on Live Demo to understand the conversion of octal number system to decimal number system.Select all the correct statements from the given statements.In octal system, the base is 10.In octal system, decimal value of 20 is represented as 21In octal system, decimal 8 is represented as 10In octal system, decimal of 10 is written as 012
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