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#include<stdio.h>int main(){char c='A';switch(c){case 64+1: printf("hello ");break;case 8*8+4: printf("world ");break;default: printf("myworld");}printf("welcome");}

Question

#include<stdio.h>int main(){char c='A';switch(c){case 64+1: printf("hello ");break;case 8*8+4: printf("world ");break;default: printf("myworld");}printf("welcome");}

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Solution

The given code is written in C language. It's a simple program that uses a switch case statement to print different strings based on the value of the character 'c'.

Here's a step-by-step explanation:

  1. The program starts with the inclusion of the standard input-output library using #include<stdio.h>.

  2. The main() function is declared, which is the entry point of the program.

  3. Inside the main() function, a character variable 'c' is declared and initialized with 'A'.

  4. A switch case statement is used with 'c' as the controlling expression.

  5. The first case is 64+1, which equals 65. The ASCII value of 'A' is also 65, so this case matches. The string "hello " is printed and the control breaks out of the switch case.

  6. The second case is 8*8+4, which equals 68. This case does not match with the ASCII value of 'c', so it is skipped.

  7. The default case is used to handle all other cases that do not match any of the specified cases. In this program, it will not be executed because 'c' matches with the first case.

  8. After the switch case statement, the string "welcome" is printed.

  9. The main() function returns 0, indicating successful execution of the program.

So, when you run this program, it will print "hello welcome".

This problem has been solved

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