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What will be the output of the following code?#include <stdio.h>int main() {    char str[] = "Programming";    printf("%s\n", str + 3);    return 0;}

Question

What will be the output of the following code?#include <stdio.h>int main() {    char str[] = "Programming";    printf("%s\n", str + 3);    return 0;}

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Solution

The output of the code will be "gramming".

Here's the step by step explanation:

  1. The code declares a character array str[] and initializes it with the string "Programming".

  2. The printf function is used to print a string. However, instead of printing the whole string, it prints from str + 3.

  3. In C, strings are arrays of characters. So, when you do str + 3, it means you're moving 3 positions forward in the array.

  4. The string "Programming" starts at index 0. So, str + 3 will point to the 4th character of the string, which is 'g'.

  5. Therefore, printf("%s\n", str + 3); will print the string starting from 'g', which is "gramming".

  6. The program then returns 0 and ends.

This problem has been solved

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