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1, 3, 4, 8, 15, 27, (.....)(a) 37 (b) 44(c) 50 (d) 55

Question

1, 3, 4, 8, 15, 27, (.....)(a) 37 (b) 44(c) 50 (d) 55

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Solution

This appears to be a sequence where each number is the sum of the two preceding numbers.

Let's break it down:

1 + 3 = 4 3 + 4 = 7 4 + 8 = 12 8 + 15 = 23 15 + 27 = 42

However, the sequence given is:

1, 3, 4, 8, 15, 27

So, it seems like the sequence is not exactly the sum of the two preceding numbers. Let's try another approach:

3 - 1 = 2 4 - 3 = 1 8 - 4 = 4 15 - 8 = 7 27 - 15 = 12

So, the difference between consecutive numbers is increasing by 1, 3, 3, 7, 12. This sequence is not regular either.

Given the options (a) 37 (b) 44(c) 50 (d) 55, none of them seem to fit into the sequence based on the patterns we've tried.

Could you please confirm if there's a mistake in the sequence or the options?

This problem has been solved

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