The given information states that the saturation current (Is) of a silicon diode is 10^-14 A at 25°C and that Is increases by 15% for each degree Celsius rise in temperature.

To find the value of Is at 125°C, we first need to find the temperature difference.

The temperature difference (ΔT) is 125°C - 25°C = 100°C.

Since the saturation current increases by 15% for each degree Celsius rise in temperature, the saturation current at 125°C will be the saturation current at 25°C multiplied by (1 + 15/100) raised to the power of the temperature difference.

So, Is at 125°C = Is at 25°C * (1 + 15/100)^ΔT
= 10^-14 A * (1 + 0.15)^100
= 10^-14 A * 1.15^100

Now, calculate the value of 1.15^100 and multiply it by 10^-14 A to get the value of Is at 125°C.

Question

The given information states that the saturation current (Is) of a silicon diode is 10^-14 A at 25°C and that Is increases by 15% for each degree Celsius rise in temperature.

To find the value of Is at 125°C, we first need to find the temperature difference.

The temperature difference (ΔT) is 125°C - 25°C = 100°C.

Since the saturation current increases by 15% for each degree Celsius rise in temperature, the saturation current at 125°C will be the saturation current at 25°C multiplied by (1 + 15/100) raised to the power of the temperature difference.

So, Is at 125°C = Is at 25°C * (1 + 15/100)^ΔT
= 10^-14 A * (1 + 0.15)^100
= 10^-14 A * 1.15^100

Now, calculate the value of 1.15^100 and multiply it by 10^-14 A to get the value of Is at 125°C.

Knowee AI · Accepted Answer

The given information states that the saturation current (Is) of a silicon diode is 10^-14 A at 25°C and that Is increases by 15% for each degree Celsius rise in temperature.

To find the value of Is at 125°C, we first need to find the temperature difference.

The temperature difference (ΔT) is 125°C - 25°C = 100°C.

Since the saturation current increases by 15% for each degree Celsius rise in temperature, the saturation current at 125°C will be the saturation current at 25°C multiplied by (1 + 15/100) raised to the power of the temperature difference.

So, Is at 125°C = Is at 25°C * (1 + 15/100)^ΔT
= 10^-14 A * (1 + 0.15)^100
= 10^-14 A * 1.15^100

Now, calculate the value of 1.15^100 and multiply it by 10^-14 A to get the value of Is at 125°C.

using the fact that silicon diode has Is=10^-14 at 25 degree celcius annd Is increases by 15% per degree celcius rise in temperature. find the value of Is at 125 degree celcius.

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