The equation of a line in slope-intercept form is given by y = mx + b, where m is the slope and b is the y-intercept.

Given that the slope (m) of the line is 0, the equation of the line becomes y = 0*x + b, or simply y = b.

The line passes through the point (-10, -6). This means that when x = -10, y = -6.

Since the equation of the line is y = b, and we know that y = -6, we can conclude that b = -6.

Therefore, the equation of the line with a slope of 0 and passing through the point (-10, -6) is y = -6.

Question

The equation of a line in slope-intercept form is given by y = mx + b, where m is the slope and b is the y-intercept.

Given that the slope (m) of the line is 0, the equation of the line becomes y = 0*x + b, or simply y = b.

The line passes through the point (-10, -6). This means that when x = -10, y = -6.

Since the equation of the line is y = b, and we know that y = -6, we can conclude that b = -6.

Therefore, the equation of the line with a slope of 0 and passing through the point (-10, -6) is y = -6.

Knowee AI · Accepted Answer

The equation of a line in slope-intercept form is given by y = mx + b, where m is the slope and b is the y-intercept.

Given that the slope (m) of the line is 0, the equation of the line becomes y = 0*x + b, or simply y = b.

The line passes through the point (-10, -6). This means that when x = -10, y = -6.

Since the equation of the line is y = b, and we know that y = -6, we can conclude that b = -6.

Therefore, the equation of the line with a slope of 0 and passing through the point (-10, -6) is y = -6.

To find the equation of a line with a slope of 0 and passing through the point \((-10, -6)\),