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Test time left: 45:50 Choose the Correct Answer(s) What will be the output after the following statements? a = [(x, y) for x in [0, 2] for y in [2, 4, 0] if x!=y] print(a) Options [(0, 2), (2, 4), (2, 0), (0,4)] [(0, 2), (2, 0), (2, 4), (0,4)] [(2, 4), (0, 4), (0, 2), (2, 0)] [(0, 2), (0, 4), (2, 4), (2, 0)]

Question

Test time left: 45:50 Choose the Correct Answer(s) What will be the output after the following statements?

a = [(x, y) for x in [0, 2] for y in [2, 4, 0] if x!=y] print(a) Options [(0, 2), (2, 4), (2, 0), (0,4)] [(0, 2), (2, 0), (2, 4), (0,4)] [(2, 4), (0, 4), (0, 2), (2, 0)] [(0, 2), (0, 4), (2, 4), (2, 0)]

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Solution

The correct answer is [(0, 2), (0, 4), (2, 4), (2, 0)].

Here's the step by step explanation:

  1. The given code is a list comprehension in Python. It generates a list of tuples (x, y) for x in [0, 2] and y in [2, 4, 0] if x is not equal to y.

  2. For x=0 and y in [2, 4, 0], the tuples generated are (0, 2) and (0, 4) because 0 is not equal to 2 and 4.

  3. For x=2 and y in [2, 4, 0], the tuples generated are (2, 4) and (2, 0) because 2 is not equal to 4 and 0.

  4. So, the final list is [(0, 2), (0, 4), (2, 4), (2, 0)].

This problem has been solved

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