To solve this problem, we need to use the combination formula, which is used when the order of selection does not matter. The formula is:

C(n, k) = n! / [k!(n-k)!]

Where:
- n is the total number of items (in this case, 6 people)
- k is the number of items to choose (in this case, 3 people)
- "!" denotes a factorial, meaning the product of all positive integers up to that number.

Substituting these into the formula gives:

C(6, 3) = 6! / [3!(6-3)!] = (6*5*4) / (3*2*1) = 20

So, the correct answer is B. 20.

Question

To solve this problem, we need to use the combination formula, which is used when the order of selection does not matter. The formula is:

C(n, k) = n! / [k!(n-k)!]

Where:
- n is the total number of items (in this case, 6 people)
- k is the number of items to choose (in this case, 3 people)
- "!" denotes a factorial, meaning the product of all positive integers up to that number.

Substituting these into the formula gives:

C(6, 3) = 6! / [3!(6-3)!] = (6*5*4) / (3*2*1) = 20

So, the correct answer is B. 20.

Knowee AI · Accepted Answer

To solve this problem, we need to use the combination formula, which is used when the order of selection does not matter. The formula is:

C(n, k) = n! / [k!(n-k)!]

Where:
- n is the total number of items (in this case, 6 people)
- k is the number of items to choose (in this case, 3 people)
- "!" denotes a factorial, meaning the product of all positive integers up to that number.

Substituting these into the formula gives:

C(6, 3) = 6! / [3!(6-3)!] = (6*5*4) / (3*2*1) = 20

So, the correct answer is B. 20.

How many group combinations of 3 can I make of 6 people?A.30B.20C.60D.10

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