The potential difference across a resistor of resistance 10 Ω, if 1020 electrons. Now through it in one second, is _____V.Select an answerA320B400C80D160

To solve this problem, we need to use the formula for current (I) and Ohm's law (V=IR).

Step 1: Calculate the current (I) The current (I) in a circuit is given by the formula I = Q/t, where Q is the charge and t is the time.

Given that 1020 electrons pass through the resistor in one second, the charge (Q) is equal to the charge of one electron (1.6 x 10^-19 Coulombs) multiplied by the number of electrons (1020).

So, Q = 1.6 x 10^-19 C/electron x 1020 electrons = 1.632 x 10^-15 Coulombs.

Since the electrons pass through the resistor in one second, t = 1 second.

Therefore, I = Q/t = 1.632 x 10^-15 C / 1 s = 1.632 x 10^-15 A.

Step 2: Use Ohm's law to calculate the potential difference (V) Ohm's law states that the potential difference (V) across a resistor is equal to the current (I) through the resistor multiplied by the resistance (R) of the resistor.

Given that the resistance (R) of the resistor is 10 Ohms,

V = IR = 1.632 x 10^-15 A x 10 Ω = 1.632 x 10^-14 V.

So, the potential difference across the resistor is 1.632 x 10^-14 V.

However, none of the options (A320, B400, C80, D160) match this answer. It seems there might be a mistake in the question or the given options.