The simplification of(NOT p) OR (p AND q) OR [p AND (NOT(NOT p OR q))]isQuestion 13Answera.True.b.False.c.p.d.q.e.None of the Given Choices.
Question
The simplification of(NOT p) OR (p AND q) OR [p AND (NOT(NOT p OR q))]isQuestion 13Answera.True.b.False.c.p.d.q.e.None of the Given Choices.
Solution
Sure, let's simplify the expression step by step:
Given expression: (NOT p) OR (p AND q) OR [p AND (NOT(NOT p OR q))]
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Simplify the innermost part first: NOT(NOT p OR q)
- Apply De Morgan's law: NOT(NOT p OR q) = (p AND NOT q)
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Substitute back into the expression: (NOT p) OR (p AND q) OR [p AND (p AND NOT q)]
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Simplify the term inside the brackets: p AND (p AND NOT q) = p AND p AND NOT q = p AND NOT q
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Substitute back into the expression: (NOT p) OR (p AND q) OR (p AND NOT q)
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Apply the distributive property: (NOT p) OR [(p AND q) OR (p AND NOT q)] = (NOT p) OR [p AND (q OR NOT q)]
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Simplify inside the brackets: q OR NOT q is always true (a tautology), so: (NOT p) OR [p AND true] = (NOT p) OR p
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Simplify the final expression: (NOT p) OR p is always true (a tautology).
Therefore, the simplification of the given expression is: a. True.
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