The ratio between length and breadth of a rectangle is 6:5. What is the sum of double the length and one-fifth of the breadth of rectangle if its area is 270²?Choices:- 41m 39m 42m 45m
Question
The ratio between length and breadth of a rectangle is 6:5. What is the sum of double the length and one-fifth of the breadth of rectangle if its area is 270²?Choices:- 41m 39m 42m 45m
Solution
To solve this problem, we first need to find the length and breadth of the rectangle.
Step 1: We know that the area of a rectangle is given by the formula length * breadth. In this case, the area is given as 270 square meters.
Step 2: We also know that the ratio of the length to the breadth is 6:5. Let's assume 6x as the length and 5x as the breadth.
Step 3: So, we can set up the equation 6x * 5x = 270. Solving this equation gives us x = √9 = 3.
Step 4: Therefore, the length of the rectangle is 63 = 18m and the breadth is 53 = 15m.
Step 5: The problem asks for the sum of double the length and one-fifth of the breadth. So, we calculate 218 + 1/515 = 36 + 3 = 39m.
So, the correct answer is 39m.
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