The graph represents the movement of a body accelerating from rest.After 5 seconds how far has the body moved?*1 point

Initially a body is a rest. If its acceleration is 5ms−2 then the distance travelled in the 18th second is:

A body rises vertically upward to a height of 100 m, in 5 seconds, then comes back to the same position after another 5 s. Find the distance travelled in m.

For the velocity-time graph shown in figure below the distance covered by the body in last two seconds of its motion is what fraction of the total distance covered by it in seven seconds :-

A particle moves a distance x in time t according to equation x = (t + 5)–1. The acceleration of the particle is proportional to :(velocity)3/2 (distance)2 (distance)–2(velocity)2/3

(b) Find the acceleration of the body. (c) Draw the shape of distance-time graph for this type of motion.