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Five children – A through E – were playing a game. In each round of the game, each child independently picked a digit from 0 to 9 and after each of the five children had picked a digit, the five digits were used to form the largest possible number that can be made with the five digits (by placing them next to each other). This number is labelled as the Ceiling Number of that round. After exactly four rounds, the child who picked the leftmost digit of the highest Ceiling Number across the four rounds is declared the winner of the game. No child can pick the same number across any two rounds.The Ceiling Number of each round are 98551, 75311, 98765 and 76544, not necessarily in any particular order.It is also known thatB picked consecutive digits across the four rounds, but not necessarily in any order, and in none of the rounds did the digit that he picked become the leftmost digit of the Ceiling Number.In each round, the digit that B picked was higher than the one that D picked, while, in the second round, C and E picked the same digit.The child who was declared the winner picked the least digit of the Ceiling Number in only one round, which was the third round.For only one child was the difference between the highest digit that he picked and the lowest digit that he picked 8, and this child picked his least digit in the first round.No one picked the same digit as D in any round and D and E did not pick consecutive digits in any round.Question No. 7DIRECTIONS for question 7: Type in your answer in the input box provided below the question.Which digit did C pick in the first round?

Question

Five children – A through E – were playing a game. In each round of the game, each child independently picked a digit from 0 to 9 and after each of the five children had picked a digit, the five digits were used to form the largest possible number that can be made with the five digits (by placing them next to each other). This number is labelled as the Ceiling Number of that round. After exactly four rounds, the child who picked the leftmost digit of the highest Ceiling Number across the four rounds is declared the winner of the game. No child can pick the same number across any two rounds.The Ceiling Number of each round are 98551, 75311, 98765 and 76544, not necessarily in any particular order.It is also known thatB picked consecutive digits across the four rounds, but not necessarily in any order, and in none of the rounds did the digit that he picked become the leftmost digit of the Ceiling Number.In each round, the digit that B picked was higher than the one that D picked, while, in the second round, C and E picked the same digit.The child who was declared the winner picked the least digit of the Ceiling Number in only one round, which was the third round.For only one child was the difference between the highest digit that he picked and the lowest digit that he picked 8, and this child picked his least digit in the first round.No one picked the same digit as D in any round and D and E did not pick consecutive digits in any round.Question No. 7DIRECTIONS for question 7: Type in your answer in the input box provided below the question.Which digit did C pick in the first round?

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Solution

To solve this problem, we need to analyze the information given and make deductions accordingly.

  1. B picked consecutive digits across the four rounds, but not necessarily in any order, and in none of the rounds did the digit that he picked become the leftmost digit of the Ceiling Number. This means B picked 4 consecutive numbers from 0 to 9, but none of them can be 9 because 9 is the leftmost digit in two of the Ceiling Numbers. So, the only possible numbers B could have picked are 1, 2, 3, 4.

  2. In each round, the digit that B picked was higher than the one that D picked. This means D picked numbers that are less than 1, 2, 3, 4. So, D could have picked 0, 1, 2, 3.

  3. In the second round, C and E picked the same digit. Since no child can pick the same number across any two rounds, C and E must have picked different numbers in the other rounds.

  4. The child who was declared the winner picked the least digit of the Ceiling Number in only one round, which was the third round. This means the winner picked 1 in the third round. Since B picked 1 in one of the rounds and B is not the winner, the winner must be A, C, D, or E.

  5. For only one child was the difference between the highest digit that he picked and the lowest digit that he picked 8, and this child picked his least digit in the first round. This means one child picked 0 and 8 in different rounds, and this child picked 0 in the first round. Since D could have picked 0, D must be this child. So, D picked 0, 1, 2, 3 and D picked 0 in the first round.

  6. No one picked the same digit as D in any round and D and E did not pick consecutive digits in any round. This means E did not pick 0, 1, 2, 3, and E did not pick numbers that are consecutive to 0, 1, 2, 3. So, E could have picked 5, 6, 7, 8, 9.

From the above analysis, we can conclude that C picked 5 in the first round.

This problem has been solved

Similar Questions

There are 8 players. Each player chooses one of the numbers 2, 3, 4, 5, 6, 7, 8, 9 or 10. The player or players whose number(s) is (are) closest to twice of the average of all numbers chosen wins. The payoff of each player is 1 if she wins (regardless of whether or not there are other winners), and 0 if she loses.What is true in this guessing game? None of the other alternatives is true. For each player, choosing the number 2 is the only strategy that survives iterated elimination of strongly dominated strategies. For each player, choosing the number 10 is the strongly dominant strategy. No player has a strongly dominant strategy. For each player, choosing the number 10 is the only strategy that survives iterated elimination of strongly dominated strategies. Every player has a strongly dominated strategy.

There are 2 teams, each having N players. There will be N rounds played between the 2 teams. In every round, a player from team A plays against a player from team B. The more powerful player wins the game. Given the strength of the players of both teams, you have to find the maximum number of rounds team A can win. Note that a player cannot play more than 1 round.Input FormatThe first line of input contains T - the number of test cases. It's followed by 3T lines. The first line contains the N - the size of the team. The next 2 lines contain N numbers each - the strength of the players of team A and team B respectively.Output FormatFor each test case, print the maximum number of rounds team A can win, separated by a new line.Constraints1 <= T <= 5001 <= N <= 100000 <= A[i], B[i] <= 10000ExampleInput341 5 7 4 3 8 2 10 22 3 10 5 33 7 10 5 20 15 Output201ExplanationTest-Case 1Player with strength 5 in team A can defeat player with strength 3 in team B.Player with strength 7 in team A can defeat player with strength 2 in team B.Test-Case 2No Player in team A can defeat any player in team B.Test-Case 3Player with strength 7 in team A can defeat player with strength 5 in team B.

There are 2 teams, each having N players. There will be N rounds played between the 2 teams. In every round, a player from team A plays against a player from team B. The more powerful player wins the game. Given the strength of the players of both the teams, you have to find the maximum number of rounds team A can win. Note that a player cannot play more than 1 round.Input FormatFirst line of input contains T - number of test cases. Its followed by 3T lines. The first line contains N - size of the team. The next 2 lines contains N numbers each - strength of the players of team A and team B respectively.Constraints1 <= T <= 5001 <= N <= 100000 <= A[i], B[i] <= 10000Output FormatFor each test case, print the maximum number of rounds team A can win, separated by newline.Sample Input 0341 5 7 4 3 8 2 10 22 3 10 5 33 7 10 5 20 15 Sample Output 0201Explanation 0Test Case 1Player with strength 5 in team A can defeat player with strength 3 in team B.Player with strength 7 in team A can defeat player with strength 2 in team B.Test Case 2No Player in team A can defeat any player in team B.Test Case 3Player with strength 7 in team A can defeat player with strength 5 in team B.

The difference between the greatest five digit number and the greatest five digit number with all different digit is

A lottery director wanted to fairly choose four winners from a group of 41 participants.He assigned each participant a two-digit number from 01 to 41.(Let's consider "01", "02", etc. to be two-digit numbers.)He then selected the following line from a random number table.11548 55865 07304 47090 23637 57011 52861Starting from the left, he used the line above to form two-digit numbers as follows.11 54 85 ...Using this new list and starting from the left, he chose four two-digit numbers from 01 to 41.He skipped numbers he had already chosen, the number 00, and numbers greater than 41.The participants who were assigned these two-digit numbers were chosen.Which four participants were selected as the winners?Participant, Participant, Participant, Participant

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