Fill in the missing codeThe given sample code finds the transpose of a given matrix using array of pointers.Fill in the missing code so that it produces the desired output.Sample Test CasesTest Case 1:Expected Output:Enter·the·order·of·matrix·:·2 3Enter·6·elements·:·1 2 3 4 5 6The·given·matrix·is1·2·3·4·5·6·Transpose·of·the·given·matrix·is1·4·2·5·3·6·

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Solution

Here is the C code to find the transpose of a matrix using array of pointers:

#include<stdio.h>
#include<stdlib.h>

int main() {
    int m, n, i, j;
    printf("Enter the order of matrix : ");
    scanf("%d %d", &m, &n);
    int **a = (int **)malloc(m * sizeof(int *));
    for(i=0; i<m; i++)
         a[i] = (int *)malloc(n * sizeof(int));
    printf("Enter %d elements : ", m*n);
    for(i = 0; i < m; i++)
        for(j = 0; j < n; j++)
            scanf("%d", &a[i][j]);
    printf("The given matrix is\n");
    for(i = 0; i < m; i++) {
        for(j = 0; j < n; j++)
            printf("%d ", a[i][j]);
        printf("\n");
    }
    printf("Transpose of the given matrix is\n");
    for(i = 0; i < n; i++) {
        for(j = 0; j < m; j++)
            printf("%d ", a[j][i]);
        printf("\n");
    }
    return 0;
}

This code first takes the order of the matrix as input, then dynamically allocates memory for the matrix using malloc. It then takes the elements of the matrix as input, prints the given matrix, and finally prints the transpose of the matrix. The transpose is obtained by interchanging the rows and columns of the matrix.

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