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In open chain structure, how many chiral carbon atoms in D-(-)-Ribose ?3425

Question

In open chain structure, how many chiral carbon atoms in D-(-)-Ribose ?3425

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Solution

D-(-)-Ribose is a monosaccharide with a five-carbon sugar (pentose). In its open chain form, it has four chiral carbon atoms. Here's how you can determine this:

  1. Identify the carbon atoms in the molecule. Ribose has five carbon atoms.

  2. Determine which carbon atoms are attached to four different types of groups. A chiral carbon atom is defined as a carbon atom that is attached to four different types of groups.

  3. In D-(-)-Ribose, the 1st, 2nd, 3rd, and 4th carbon atoms are each attached to -H, -OH, -CHO or -CH2OH, and -CH(OH). The asterisk () represents the remaining carbon atoms in the chain.

  4. Therefore, D-(-)-Ribose has four chiral carbon atoms in its open chain structure.

This problem has been solved

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