A 4500-kg truck traveling due east at a speed of 101 km/h approaches a 650-kg car traveling due west at 130 km/h. The net momentum of the system consisting of the car and truck isMultiple Choice
Question
A 4500-kg truck traveling due east at a speed of 101 km/h approaches a 650-kg car traveling due west at 130 km/h. The net momentum of the system consisting of the car and truck isMultiple Choice
Solution
The momentum of an object is calculated by multiplying its mass by its velocity. In this case, we need to calculate the momentum of both the truck and the car and then combine them to find the net momentum of the system.
Step 1: Convert the speeds from km/h to m/s because the standard unit of velocity in physics is m/s.
1 km/h = 0.27778 m/s
So, the truck's speed is 101 km/h * 0.27778 = 28.07 m/s And the car's speed is 130 km/h * 0.27778 = 36.11 m/s
Step 2: Calculate the momentum of the truck and the car.
The truck's momentum is its mass times its velocity, or 4500 kg * 28.07 m/s = 126315 kgm/s The car's momentum is 650 kg * 36.11 m/s = 23471.5 kgm/s
Step 3: Calculate the net momentum of the system.
Because the truck and the car are moving in opposite directions, we subtract the car's momentum from the truck's momentum.
So, the net momentum is 126315 kgm/s - 23471.5 kgm/s = 102843.5 kg*m/s
Therefore, the net momentum of the system consisting of the car and truck is 102843.5 kg*m/s.
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