Use the graph to state the absolute and local maximum and minimum values of the function. (Assume each point lies on the gridlines. Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)A function with two curves, three closed points, and three open points is graphed on the x y coordinate plane. The first curve begins at the closed point (0, 2) increases to the open point (1, 4) decreases to (2, 2) increases to (4, 5) decreases to (5, 3) then turns sharply and increases to the closed point (6, 4). The second curve begins at the open point (6, 3) and decreases to the open point (7, 1). The closed point (1, 3) is graphed.absolute maximum value 5 absolute minimum value 2 local maximum value(s) 5 local minimum value(s) 2,3

The graph of a function f is given in the figure.A curve is shown on the x y coordinate plane. It begins at the point (−2, −1), goes up and to the right, passes through the approximate point (−1, −0.2), and passes through the negative x-axis at the approximate point (−0.8, 0). It then continues up and right, passes through the positive y-axis at the point (0, 1), and reaches a high point at (1, 3). It then goes down and right, passes through the points (2, 2) and (3, 1), and ends at the approximate point (4, 0.5).(a)Find the value of f(1).(b)Estimate the value of f(−1).(c)For what values of x is f(x) = 1? (Enter your answers as a comma-separated list.) (d)Estimate the value of x such that f(x) = 0.x = (e)State the domain and range of f. (Enter your answers in interval notation.)domain range (f)On what interval is f increasing? (Enter your answer using interval notation.)

The graph of a function g is shown.The x y-coordinate plane is given. A function labeled y = g(x) with 4 parts is graphed.The first part is a curve, enters the window in the second quadrant, goes up and right becoming less steep, crosses the y-axis at approximately y = 2.5, and ends at the open point (2, 3).The second part is a curve begins again at the open point (2, 1), goes up and right becoming less steep, and ends at the open point (5, 2).The third part is the closed approximate point (5, 1.2).The fourth part is a curve, begins at the open point (5, 2) goes down and right becoming more steep, and exits the window in the first quadrant.Use it to state the values (if they exist) of the following:(a)  lim x → 2− g(x)(b)  lim x → 2+ g(x)(c)  lim x → 2 g(x)(d)  lim x → 5− g(x)(e)  lim x → 5+ g(x)(f)  lim x → 5 g(x)SolutionLooking at the graph we see that the values of g(x) approach as x approaches 2 from the left, but they approach as x approaches 2 from the right.Therefore (a) lim x → 2− g(x) =     and    (b) lim x → 2+ g(x) = .Since the left and right limits are different, we conclude that (c) the limit as x approaches 2 of g(x) does not exist.The graph also shows that (d) lim x → 5− g(x) =     and    (e) lim x → 5+ g(x) = .This time, the left and right limits are the same and so, by this theorem, we have (f) lim x → 5 g(x) = Despite this fact, notice that g(5) ≠ 2.

Use the graph to determine the open intervals over which  is increasing, decreasing, or constant, then determine all the local minimum and maximum values on the graph.a.)Increasing on Decreasing on Local minimum is 1 at Local maximum is -1 at b.)Increasing on Decreasing on Local minimum is 2 at Local maximum is 6 at c.)Increasing on Decreasing on Local minimum is 1 at Local maximum is -1 at d.)Increasing on Decreasing on Local minimum is 2 at Local maximum is 6 at

he graph of a function f is given. Use the graph to estimate the following.(a) All the local maximum and minimum values of the function and the value of x at which each occurslocal maximum     (x, y) = 0,12 local minimum      (x, y) = −9,−6 (smaller x-value)local minimum (x, y) = 6,3 (larger x-value)(b) The intervals on which the function is increasing and on which the function is decreasing. (Enter your answers using interval notation.)increasing     (−∞,−9)∪(0,6) decreasing     (0,6)

The graph of a function g is shown. The x y-coordinate plane is given. The curve begins at the point (−2, 0), goes up and right, passes through the point (−1.5, 1), goes up and right, changes direction at the point (−1, 1.5), goes down and right, passes through the point (−0.5, 1), goes down and right, passes through the origin, goes down and right, passes through the point (0.5, −1), goes down and right, changes direction at the point (1, −1.5), goes up and right, passes through the point (1.5, −0.5), goes up and right, changes direction at the point (2, 0.5), goes down and right, crosses the x-axis at x = 2.5, goes down and right, changes direction at the point (3, −1), goes up and right, passes through the point (3.5, −0.5), goes up and right, and ends at the point (4, 0.5). Estimate 4 −2 g(x) dx with six subintervals using the following. (a) right endpoints 0 Correct: Your answer is correct. (b) left endpoints -0.5 Correct: Your answer is correct. (c) midpoints