The problem involves a process of dilution where a certain volume of milk is replaced by water multiple times. Here's how to solve it:

1. Start with 80 L of milk.
2. In the first operation, 8 L of milk is taken out. The amount of milk left is 80 L - 8 L = 72 L.
3. The process is repeated, so we take out 8 L of the mixture again. However, since the mixture is now 90% milk and 10% water, we're only removing 90% of 8 L of milk. So, we subtract 8 L * 0.9 = 7.2 L of milk from the remaining 72 L, leaving us with 72 L - 7.2 L = 64.8 L of milk.
4. The process is repeated one more time. Again, we're removing 90% of 8 L of milk from the mixture. So, we subtract 8 L * 0.9 = 7.2 L of milk from the remaining 64.8 L, leaving us with 64.8 L - 7.2 L = 57.6 L of milk.

So, the volume of milk left in the container after the process is repeated twice is approximately 57.6 L. However, none of the choices exactly match this result. The closest choice is 58.23 L, which might be due to rounding errors in the problem statement or in our calculations.

Question

The problem involves a process of dilution where a certain volume of milk is replaced by water multiple times. Here's how to solve it:

1. Start with 80 L of milk.
2. In the first operation, 8 L of milk is taken out. The amount of milk left is 80 L - 8 L = 72 L.
3. The process is repeated, so we take out 8 L of the mixture again. However, since the mixture is now 90% milk and 10% water, we're only removing 90% of 8 L of milk. So, we subtract 8 L * 0.9 = 7.2 L of milk from the remaining 72 L, leaving us with 72 L - 7.2 L = 64.8 L of milk.
4. The process is repeated one more time. Again, we're removing 90% of 8 L of milk from the mixture. So, we subtract 8 L * 0.9 = 7.2 L of milk from the remaining 64.8 L, leaving us with 64.8 L - 7.2 L = 57.6 L of milk.

So, the volume of milk left in the container after the process is repeated twice is approximately 57.6 L. However, none of the choices exactly match this result. The closest choice is 58.23 L, which might be due to rounding errors in the problem statement or in our calculations.

Knowee AI · Accepted Answer

The problem involves a process of dilution where a certain volume of milk is replaced by water multiple times. Here's how to solve it:

1. Start with 80 L of milk.
2. In the first operation, 8 L of milk is taken out. The amount of milk left is 80 L - 8 L = 72 L.
3. The process is repeated, so we take out 8 L of the mixture again. However, since the mixture is now 90% milk and 10% water, we're only removing 90% of 8 L of milk. So, we subtract 8 L * 0.9 = 7.2 L of milk from the remaining 72 L, leaving us with 72 L - 7.2 L = 64.8 L of milk.
4. The process is repeated one more time. Again, we're removing 90% of 8 L of milk from the mixture. So, we subtract 8 L * 0.9 = 7.2 L of milk from the remaining 64.8 L, leaving us with 64.8 L - 7.2 L = 57.6 L of milk.

So, the volume of milk left in the container after the process is repeated twice is approximately 57.6 L. However, none of the choices exactly match this result. The closest choice is 58.23 L, which might be due to rounding errors in the problem statement or in our calculations.

A container has 80 L of milk. From this container 8 L of milk was taken out and replaced by water. The process was further repeated twice. The volume of milk in the container after that isChoices:- 58.23 L 85.23 L 58.32 L 85.32 L

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