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Consider the below left-left rotation pseudo code where the node contains value pointers to left, right child nodes and a height value and Height() function returns height value stored at a particular node.avltree leftrotation(avltreenode z): avltreenode w =x-left x-left=w-right w-right=x x-height=max(Height(x-left),Height(x-right))+1 w-height=max(missing)+1 return w*2 pointsHeight(w-left), x-heightHeight(w-right), x-heightHeight(w-left), xHeight(w-left)

Question

Consider the below left-left rotation pseudo code where the node contains value pointers to left, right child nodes and a height value and Height() function returns height value stored at a particular node.avltree leftrotation(avltreenode z): avltreenode w =x-left x-left=w-right w-right=x x-height=max(Height(x-left),Height(x-right))+1 w-height=max(missing)+1 return w*2 pointsHeight(w-left), x-heightHeight(w-right), x-heightHeight(w-left), xHeight(w-left)

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Solution 1

To perform a left-left rotation in an AVL tree, follow the steps outlined in the given pseudo code:

  1. Create a variable "w" and set it equal to the left child of node "x" (w = x-left).
  2. Update the left child of node "x" by assigning it the right child of node "w" (x-left = w-right).
  3. Update the right child of node "w" by assigning it node "x" (w-right = x).
  4. Update the height of node "x" by taking the maximum value between the heights of its left and right children, and adding 1 (x-height = max(Height(x-left), Height(x-right)) + 1).
  5. Update the height of node "w" by adding 1 to the maximum height value (w-height = max(missing) + 1).
  6. Return the updated node "w".

Please note that the pseudo code provided is incomplete and contains some missing values (e.g., "missing" in step 5). It is important to have the complete and correct pseudo code to accurately perform the left-left rotation in an AVL tree.

This problem has been solved

Solution 2

To perform a left-left rotation in an AVL tree, follow the steps outlined in the given pseudo code:

  1. Create a variable "w" and set it equal to the left child of node "x" (w = x-left).
  2. Update the left child of node "x" by assigning it the right child of node "w" (x-left = w-right).
  3. Update the right child of node "w" by assigning it node "x" (w-right = x).
  4. Update the height of node "x" by taking the maximum value between the heights of its left and right children, and adding 1 (x-height = max(Height(x-left), Height(x-right)) + 1).
  5. Update the height of node "w" by adding 1 to the maximum height value (w-height = max(missing) + 1).
  6. Return the updated node "w".

Please note that the pseudo code provided seems to have some missing or incorrect information, such as the calculation of missing values and the multiplication of "w" by 2.

This problem has been solved

Similar Questions

What is missing in the below-given code?1234567avltree leftrotation(avltreenode z): avltreenode w =x-left x-left=w-right w-right=x x-height=max(Height(x-left),Height(x-right))+1 w-height=max(missing)+1 return w

What is the primary purpose of performing rotations in an AVL tree?a)To create new child nodesb)To maintain or restore balancec)To delete nodes with duplicate valuesd)To increase the height of the tree

Which rotations in AVL trees are known as single rotations?

In AVL Tree Balancing is done if the Balance Factor of a node is

int avl(binarysearchtree root): if(not root) return 0 left_tree_height = avl(left_of_root)  if(left_tree_height== -1) return left_tree_height  right_tree_height= avl(right_of_root)  if(right_tree_height==-1) return right_tree_heightDoes the above code can check if a binary search tree is an AVL tree?  *2 pointsyesno

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