This problem is about bit manipulation. Here is a step-by-step solution in Python: 1. First, we need to understand how to swap adjacent bits. For a binary number, the even bits are at positions 0, 2, 4, etc. and the odd bits are at positions 1, 3, 5, etc. We can get the even bits by bitwise AND operation of the number with 0xAAAAAAAA (A in hexadecimal is 1010 in binary). Similarly, we can get the odd bits by bitwise AND operation of the number with 0x55555555 (5 in hexadecimal is 0101 in binary). 2. After getting the even and odd bits, we can swap them by right shifting the even bits and left shifting the odd bits. 3. Finally, we can get the result by bitwise OR operation of the shifted even and odd bits. Here is the Python code for the problem: ```python T = int(input()) for _ in range(T): N = int(input()) even_bits = N & 0xAAAAAAAA odd_bits = N & 0x55555555 even_bits = 1 odd_bits

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This problem is about bit manipulation. Here is a step-by-step solution in Python: 1. First, we need to understand how to swap adjacent bits. For a binary number, the even bits are at positions 0, 2, 4, etc. and the odd bits are at positions 1, 3, 5, etc. We can get the even bits by bitwise AND operation of the number with 0xAAAAAAAA (A in hexadecimal is 1010 in binary). Similarly, we can get the odd bits by bitwise AND operation of the number with 0x55555555 (5 in hexadecimal is 0101 in binary). 2. After getting the even and odd bits, we can swap them by right shifting the even bits and left shifting the odd bits. 3. Finally, we can get the result by bitwise OR operation of the shifted even and odd bits. Here is the Python code for the problem: ```python T = int(input()) for _ in range(T): N = int(input()) even_bits = N & 0xAAAAAAAA odd_bits = N & 0x55555555 even_bits >>= 1 odd_bits <<= 1 result = even_bits | odd_bits print(result) ``` This code first reads the number of test cases. For each test case, it reads the number, gets the even and odd bits, swaps them, and prints the result.

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This problem is about bit manipulation. Here is a step-by-step solution in Python: 1. First, we need to understand how to swap adjacent bits. For a binary number, the even bits are at positions 0, 2, 4, etc. and the odd bits are at positions 1, 3, 5, etc. We can get the even bits by bitwise AND operation of the number with 0xAAAAAAAA (A in hexadecimal is 1010 in binary). Similarly, we can get the odd bits by bitwise AND operation of the number with 0x55555555 (5 in hexadecimal is 0101 in binary). 2. After getting the even and odd bits, we can swap them by right shifting the even bits and left shifting the odd bits. 3. Finally, we can get the result by bitwise OR operation of the shifted even and odd bits. Here is the Python code for the problem: ```python T = int(input()) for _ in range(T): N = int(input()) even_bits = N & 0xAAAAAAAA odd_bits = N & 0x55555555 even_bits >>= 1 odd_bits <<= 1 result = even_bits | odd_bits print(result) ``` This code first reads the number of test cases. For each test case, it reads the number, gets the even and odd bits, swaps them, and prints the result.

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