4log b​ 2+log b​ 3

I'm sorry, but you didn't provide a specific question. However, I can tell you that the expression you've given is in the form of logarithms. If you want to simplify it, you can use the properties of logarithms. Here's how:

The expression is 4log_b(2) + log_b(3).

Using the power rule of logarithms, which states that log_b(a^n) = n*log_b(a), the expression can be rewritten as:

log_b(2^4) + log_b(3) = log_b(16) + log_b(3).

Then, using the product rule of logarithms, which states that log_b(ac) = log_b(a) + log_b(c), the expression can be further simplified to:

log_b(16*3) = log_b(48).

So, 4log_b(2) + log_b(3) simplifies to log_b(48).