A certain distance is covered by a cyclist at a certain speed. If a jogger covers half the distance in double the time, the ratio of the speed of the jogger to that of the cyclist is?Options1 : 41 : 22 : 14 : 1
Question
A certain distance is covered by a cyclist at a certain speed. If a jogger covers half the distance in double the time, the ratio of the speed of the jogger to that of the cyclist is?Options1 : 41 : 22 : 14 : 1
Solution
The speed of an object is determined by the distance it travels over a certain period of time. In this case, the cyclist and the jogger are both traveling the same distance, but the jogger is taking twice as long to cover half the distance.
Let's denote the distance the cyclist covers as D, and the time it takes him as T. Therefore, the speed of the cyclist (Sc) is D/T.
The jogger covers half the distance (D/2) in double the time (2T). Therefore, the speed of the jogger (Sj) is (D/2) / (2T) = D / 4T.
The ratio of the speed of the jogger to that of the cyclist is therefore Sj / Sc = (D / 4T) / (D / T) = 1 / 4.
So, the ratio of the speed of the jogger to that of the cyclist is 1 : 4.
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