What will be the following Python code?dict1={"a":10,"b":2,"c":3}str1=""for i in dict1: str1=str1+str(dict1[i])+" " str2=str1[:-1]print(str2[::-1])3,23,2,103,2,01Error

The given Python code will iterate over the dictionary dict1 and for each key, it will append the corresponding value to str1 followed by a space. The line str2=str1[:-1] will remove the last space from str1. Finally, print(str2[::-1]) will print the reverse of str2.

Here is a step-by-step explanation:

1. Initialize dict1 with keys "a", "b", "c" and corresponding values 10, 2, 3.
2. Initialize an empty string str1.
3. Iterate over each key in dict1.
4. For each key, convert the corresponding value in dict1 to a string and append it to str1 followed by a space.
5. After the loop, str1 will be "10 2 3 ".
6. str2 is assigned the value of str1 with the last character (which is a space) removed. So, str2 will be "10 2 3".
7. Finally, print the reverse of str2, which will be "3 2 01".

The given Python code will iterate over the dictionary 'dict1' and for each key, it will append the corresponding value to the string 'str1' followed by a space. The line 'str2=str1[:-1]' will create a new string 'str2' that contains all characters of 'str1' except the last one (which is a space). Finally, 'print(str2[::-1])' will print the string 'str2' in reverse order.

So, if we run the code, it will print '3 2 01'. This is because the values of the dictionary 'dict1' are 10, 2, and 3. These values are converted to strings and appended to 'str1' in the order they are retrieved from the dictionary, resulting in the string '10 2 3 '. Then, the last space is removed, and the string is reversed, resulting in '3 2 01'.