If 3x+y = 81 and 81x–y = 38, then find the values ofx and y respectively.(A) 3, 1 (B) 1, 3(C) –1, 3 (D) –1, –3
Question
If 3x+y = 81 and 81x–y = 38, then find the values ofx and y respectively.(A) 3, 1 (B) 1, 3(C) –1, 3 (D) –1, –3
Solution
To solve for x and y, we can use the method of substitution or elimination. Here, I'll use the method of elimination:
Step 1: We have the two equations: 3x + y = 81 81x - y = 38
Step 2: Add the two equations together: 3x + y + 81x - y = 81 + 38 84x = 119
Step 3: Solve for x: x = 119 / 84 x = 1.42 (approximately)
Step 4: Substitute x = 1.42 into the first equation: 3(1.42) + y = 81 4.26 + y = 81 y = 81 - 4.26 y = 76.74 (approximately)
So, the solution to the system of equations is x = 1.42 and y = 76.74. However, these values do not match any of the given options. There might be a mistake in the problem or the options provided.
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