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Single File Programming QuestionProblem StatementImagine you are working on a financial application where users input various transaction amounts. As part of a data analysis feature, you need to implement a function countZeros(int n) to count the occurrences of zeros in the transaction amounts. Write a program that uses recursion to achieve this. Input format :The input consists of an integer n, representing the transaction amount.Output format :The output prints the count of zero digits in the entered transaction amount.Refer to the sample output for formatting specifications.Code constraints :In the given scenario, the test cases fall under the following constraints:100 ≤ n ≤ 105Sample test cases :Input 1 :505Output 1 :1Input 2 :12345Output 2 :0Input 3 :100Output 3 :2

Question

Single File Programming QuestionProblem StatementImagine you are working on a financial application where users input various transaction amounts. As part of a data analysis feature, you need to implement a function countZeros(int n) to count the occurrences of zeros in the transaction amounts. Write a program that uses recursion to achieve this. Input format :The input consists of an integer n, representing the transaction amount.Output format :The output prints the count of zero digits in the entered transaction amount.Refer to the sample output for formatting specifications.Code constraints :In the given scenario, the test cases fall under the following constraints:100 ≤ n ≤ 105Sample test cases :Input 1 :505Output 1 :1Input 2 :12345Output 2 :0Input 3 :100Output 3 :2

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Solution

Here is a Python solution for the problem:

def countZeros(n):
    # base case
    if n == 0:
        return 0

    # recursive case
    if n % 10 == 0:
        return 1 + countZeros(n // 10)
    else:
        return countZeros(n // 10)

# test cases
print(countZeros(505))  # Output: 1
print(countZeros(12345))  # Output: 0
print(countZeros(100))  # Output: 2

This program works by recursively dividing the input number n by 10 (effectively removing the last digit) and checking if the last digit is 0. If it is, it adds 1 to the count. The base case for the recursion is when n becomes 0, at which point it returns the count.

This problem has been solved

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