The electric field (E) between the plates of a capacitor is given by the equation E = V/d, where V is the voltage across the plates and d is the distance between the plates.

Given that the voltage (V) is changing at a rate of 60 V/s and the distance (d) between the plates is 1.2 mm or 0.0012 m, we can find the rate of change of the electric field (dE/dt) using the chain rule of differentiation.

The chain rule states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function. In this case, the outer function is E = V/d and the inner function is V = 60t, where t is time in seconds.

So, dE/dt = d(E)/d(V) * d(V)/dt = 1/d * 60 = 60 / 0.0012 = 50000 V/m/s.

Therefore, the electric field between the plates of the capacitor is changing at a rate of 50000 V/m/s.

Question

The electric field (E) between the plates of a capacitor is given by the equation E = V/d, where V is the voltage across the plates and d is the distance between the plates.

Given that the voltage (V) is changing at a rate of 60 V/s and the distance (d) between the plates is 1.2 mm or 0.0012 m, we can find the rate of change of the electric field (dE/dt) using the chain rule of differentiation.

The chain rule states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function. In this case, the outer function is E = V/d and the inner function is V = 60t, where t is time in seconds.

So, dE/dt = d(E)/d(V) * d(V)/dt = 1/d * 60 = 60 / 0.0012 = 50000 V/m/s.

Therefore, the electric field between the plates of the capacitor is changing at a rate of 50000 V/m/s.

Knowee AI · Accepted Answer

The electric field (E) between the plates of a capacitor is given by the equation E = V/d, where V is the voltage across the plates and d is the distance between the plates.

Given that the voltage (V) is changing at a rate of 60 V/s and the distance (d) between the plates is 1.2 mm or 0.0012 m, we can find the rate of change of the electric field (dE/dt) using the chain rule of differentiation.

The chain rule states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function. In this case, the outer function is E = V/d and the inner function is V = 60t, where t is time in seconds.

So, dE/dt = d(E)/d(V) * d(V)/dt = 1/d * 60 = 60 / 0.0012 = 50000 V/m/s.

Therefore, the electric field between the plates of the capacitor is changing at a rate of 50000 V/m/s.

At what rate does the electric field change between the plates of a squarecapacitor of side 5 cm, if the plates are spaced 1.2 mm apart and the voltageacross them is changing at a rate of 60 V/s?

Question

Solution

Similar Questions

Upgrade your grade with Knowee