Q1. Which one of the following is the strongest acid?a) CH2ClCOOHb) CH3COOHc) CHCl2COOHd) CCl3COOH

The strength of an acid is determined by its ability to donate a proton (H+). In the case of carboxylic acids, the more electron-withdrawing groups attached to the molecule, the more stable the resulting anion will be after it donates a proton. This is because electron-withdrawing groups can help to disperse the negative charge, making the anion more stable and therefore making the acid stronger.

Here are the steps to determine the strongest acid:

1. Identify the electron-withdrawing groups in each molecule. In this case, the electron-withdrawing groups are the chlorine atoms (Cl).

2. Count the number of electron-withdrawing groups in each molecule.

   a) CH2ClCOOH has 1 Cl atom.

   b) CH3COOH has no Cl atoms.

   c) CHCl2COOH has 2 Cl atoms.

   d) CCl3COOH has 3 Cl atoms.

3. The molecule with the most electron-withdrawing groups will be the strongest acid.

So, the strongest acid among the given options is d) CCl3COOH because it has the most Cl atoms, which are electron-withdrawing groups.