[A]⟶ reduction [B]⟶CHCl3+KOH[C]⟶ reduction N− Methylaniline, A is?FormaldehydeTrichloromethaneNitrobenzeneToluene
Question
[A]⟶ reduction [B]⟶CHCl3+KOH[C]⟶ reduction N− Methylaniline, A is?FormaldehydeTrichloromethaneNitrobenzeneToluene
Solution
The compound A is Nitrobenzene. Here's the step by step process:
- Nitrobenzene (A) is reduced to Aniline (B) through a reduction process.
- Aniline (B) reacts with CHCl3 and KOH to form a diazonium salt (C).
- The diazonium salt (C) is then reduced to form N-Methylaniline.
So, the correct answer is Nitrobenzene.
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