The microcode instruction jmp e2h causes a jump to the statement stored in memory location e2h. Describe the steps of the fetch-execute cycle interms of the execution of this statement.
Question
The microcode instruction jmp e2h causes a jump to the statement stored in memory location e2h. Describe the steps of the fetch-execute cycle interms of the execution of this statement.
Solution
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Fetch: The first step in the fetch-execute cycle is to fetch the instruction from memory. The CPU does this by sending the address of the instruction (in this case, the address of the "jmp e2h" instruction) to the memory unit. The memory unit then sends the instruction back to the CPU.
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Decode: Once the CPU has fetched the instruction, it needs to decode it to understand what it needs to do. In this case, the CPU decodes the "jmp e2h" instruction to understand that it needs to jump to the statement stored in memory location e2h.
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Execute: After the CPU has decoded the instruction, it executes it. In this case, the CPU changes the program counter to the address e2h. This means that the next instruction that the CPU will fetch will be the one at memory location e2h, effectively causing a jump to that statement.
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Store: The final step in the fetch-execute cycle is to store the result of the instruction. In this case, since the instruction is a jump, there is no result to store. The effect of the instruction (the change in the program counter) is already in place.
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The cycle then repeats for the instruction at the new program counter location (e2h).
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