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An object moves 60.0m on a bearing (angle from North) of 60.0 ∘ . If the object then moves 30.0m North, how far is it from the start point? You may use a scale diagram or trigonometry to answer this question.Value

Question

An object moves 60.0m on a bearing (angle from North) of 60.0 ∘ . If the object then moves 30.0m North, how far is it from the start point? You may use a scale diagram or trigonometry to answer this question.Value

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Solution

To solve this problem, we can use the law of cosines. The law of cosines is a formula used in geometry to find a side of a triangle when the lengths of the other two sides and their enclosed angle are known.

Step 1: Identify the triangle The object's movement forms a triangle. The first leg of the triangle is the 60m movement on a bearing of 60 degrees. The second leg is the 30m movement north. The third leg, which we are trying to find, is the distance from the start point to the end point.

Step 2: Apply the law of cosines The law of cosines is c² = a² + b² - 2abcos(C), where a and b are the sides of the triangle, C is the angle, and c is the side we are trying to find.

In this case, a = 60m, b = 30m, and C = 60 degrees. Plugging these values into the formula gives us:

c² = 60² + 30² - 26030cos(60) c² = 3600 + 900 - 21800*0.5 c² = 4500 - 1800 c² = 2700

Step 3: Solve for c To find c, we take the square root of c²:

c = sqrt(2700) ≈ 51.96m

So, the object is approximately 51.96m from the start point.

This problem has been solved

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