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A queue is an abstract data type that maintains the order in which elements were added to it, allowing the oldest elements to be removed from the front and new elements to be added to the rear. This is called a First-In-First-Out (FIFO) data structure because the first element added to the queue (i.e., the one that has been waiting the longest) is always the first one to be removed.A basic queue has the following operations:Enqueue: add a new element to the end of the queue.Dequeue: remove the element from the front of the queue and return it.In this challenge, you must first implement a queue using two stacks. Then process queries, where each query is one of the following types:1 x: Enqueue element into the end of the queue.2: Dequeue the element at the front of the queue.3: Print the element at the front of the queue.Input FormatThe first line contains a single integer, , denoting the number of queries.Each line of the subsequent lines contains a single query in the form described in the problem statement above. All three queries start with an integer denoting the query , but only query is followed by an additional space-separated value, , denoting the value to be enqueued.ConstraintsIt is guaranteed that a valid answer always exists for each query of type .Output FormatFor each query of type , print the value of the element at the front of the queue on a new line.Sample InputSTDIN Function----- --------10 q = 10 (number of queries)1 42 1st query, enqueue 422 dequeue front element1 14 enqueue 423 print the front element1 28 enqueue 283 print the front element1 60 enqueue 601 78 enqueue 782 dequeue front element2 dequeue front elementSample Output1414ExplanationPerform the following sequence of actions:Enqueue ; .Dequeue the value at the head of the queue, ; .Enqueue ; .Print the value at the head of the queue, ; .Enqueue ; .Print the value at the head of the queue, ; .Enqueue ; .Enqueue ; .Dequeue the value at the head of the queue, ; .Dequeue the value at the head of the queue, ; .

Question

A queue is an abstract data type that maintains the order in which elements were added to it, allowing the oldest elements to be removed from the front and new elements to be added to the rear. This is called a First-In-First-Out (FIFO) data structure because the first element added to the queue (i.e., the one that has been waiting the longest) is always the first one to be removed.A basic queue has the following operations:Enqueue: add a new element to the end of the queue.Dequeue: remove the element from the front of the queue and return it.In this challenge, you must first implement a queue using two stacks. Then process queries, where each query is one of the following types:1 x: Enqueue element into the end of the queue.2: Dequeue the element at the front of the queue.3: Print the element at the front of the queue.Input FormatThe first line contains a single integer, , denoting the number of queries.Each line of the subsequent lines contains a single query in the form described in the problem statement above. All three queries start with an integer denoting the query , but only query is followed by an additional space-separated value, , denoting the value to be enqueued.ConstraintsIt is guaranteed that a valid answer always exists for each query of type .Output FormatFor each query of type , print the value of the element at the front of the queue on a new line.Sample InputSTDIN Function----- --------10 q = 10 (number of queries)1 42 1st query, enqueue 422 dequeue front element1 14 enqueue 423 print the front element1 28 enqueue 283 print the front element1 60 enqueue 601 78 enqueue 782 dequeue front element2 dequeue front elementSample Output1414ExplanationPerform the following sequence of actions:Enqueue ; .Dequeue the value at the head of the queue, ; .Enqueue ; .Print the value at the head of the queue, ; .Enqueue ; .Print the value at the head of the queue, ; .Enqueue ; .Enqueue ; .Dequeue the value at the head of the queue, ; .Dequeue the value at the head of the queue, ; .

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Solution

The problem statement is asking to implement a queue using two stacks. A queue is a First-In-First-Out (FIFO) data structure, which means the first element added is the first one to be removed.

Here are the steps to solve this problem:

  1. Initialize two stacks, stack1 and stack2.

  2. For the enqueue operation (query type 1), push the element into stack1.

  3. For the dequeue operation (query type 2), if stack2 is empty, pop all elements from stack1 and push them into stack2. Then, pop the top element from stack2. If stack2 is not empty, just pop the top element from stack2.

  4. For the print operation (query type 3), if stack2 is empty, pop all elements from stack1 and push them into stack2. Then, the top element of stack2 is the front element of the queue, print it. If stack2 is not empty, just print the top element of stack2.

The reason for using two stacks is to reverse the order of elements. When we push an element into a stack and then pop all elements out, the order of elements is reversed. So, by using two stacks, we can reverse the order of elements twice, which gives us the original order of elements, and thus we can implement a queue.

In the given example, the sequence of actions is as follows:

  • Enqueue 42; queue is now {42}
  • Dequeue; queue is now {}
  • Enqueue 14; queue is now {14}
  • Print; prints 14
  • Enqueue 28; queue is now {14, 28}
  • Print; prints 14
  • Enqueue 60; queue is now {14, 28, 60}
  • Enqueue 78; queue is now {14, 28, 60, 78}
  • Dequeue; queue is now {28, 60, 78}
  • Dequeue; queue is now {60, 78}

So, the output is 14, 14.

This problem has been solved

Similar Questions

ProblemSubmissionsLeaderboardDiscussionsA queue is an abstract data type that maintains the order in which elements were added to it, allowing the oldest elements to be removed from the front and new elements to be added to the rear. This is called a First-In-First-Out (FIFO) data structure because the first element added to the queue (i.e., the one that has been waiting the longest) is always the first one to be removed.A basic queue has the following operations:Enqueue: add a new element to the end of the queue.Dequeue: remove the element from the front of the queue and return it.In this challenge, you must first implement a queue using two stacks. Then process queries, where each query is one of the following types:1 x: Enqueue element into the end of the queue.2: Dequeue the element at the front of the queue.3: Print the element at the front of the queue.Input FormatThe first line contains a single integer, , denoting the number of queries.Each line of the subsequent lines contains a single query in the form described in the problem statement above. All three queries start with an integer denoting the query , but only query is followed by an additional space-separated value, , denoting the value to be enqueued.ConstraintsIt is guaranteed that a valid answer always exists for each query of type .Output FormatFor each query of type , print the value of the element at the front of the queue on a new line.Sample InputSTDIN Function----- --------10 q = 10 (number of queries)1 42 1st query, enqueue 422 dequeue front element1 14 enqueue 423 print the front element1 28 enqueue 283 print the front element1 60 enqueue 601 78 enqueue 782 dequeue front element2 dequeue front elementSample Output1414ExplanationPerform the following sequence of actions:Enqueue ; .Dequeue the value at the head of the queue, ; .Enqueue ; .Print the value at the head of the queue, ; .Enqueue ; .Print the value at the head of the queue, ; .Enqueue ; .Enqueue ; .Dequeue the value at the head of the queue, ; .Dequeue the value at the head of the queue, ; .

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What is the non-FIFO implementation of Queues called?a) Priority Queue.b) Circular Queue.c) Normal Queue.d) None of the above

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