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If ๐‘“(๐‘ฅ)=2๐‘ฅ+3f(x)=2x+3, ๐‘”(๐‘ฅ)=๐‘ฅ2โˆ’5g(x)=x 2 โˆ’5, and โ„Ž(๐‘ฅ)=๐‘ฅ2h(x)= 2xโ€‹ , find the value of h(g(f(4))).a116b58c11d4

Question

If ๐‘“(๐‘ฅ)=2๐‘ฅ+3f(x)=2x+3, ๐‘”(๐‘ฅ)=๐‘ฅ2โˆ’5g(x)=x 2 โˆ’5, and โ„Ž(๐‘ฅ)=๐‘ฅ2h(x)= 2xโ€‹ , find the value of h(g(f(4))).a116b58c11d4

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Solution

The question is asking for the value of h(g(f(4))). To solve this, we need to follow the order of operations, which is from the inside out.

  1. First, find the value of f(4). The function f(x) is defined as 2x + 3. So, f(4) = 2*4 + 3 = 11.

  2. Next, find the value of g(f(4)). We know that f(4) = 11, so we need to find g(11). The function g(x) is defined as x^2 - 5. So, g(11) = 11^2 - 5 = 116.

  3. Finally, find the value of h(g(f(4))). We know that g(f(4)) = 116, so we need to find h(116). The function h(x) is defined as x^2. So, h(116) = 116^2 = 13456.

So, the value of h(g(f(4))) is 13456.

This problem has been solved

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