X is a 5 digit number. Let Y be the sum of the digits ofX. Let Z be the sum of the digits of Y. Then themaximum possible value of that Z can have is
Question
X is a 5 digit number. Let Y be the sum of the digits ofX. Let Z be the sum of the digits of Y. Then themaximum possible value of that Z can have is
Solution
The maximum possible value of a digit in a number is 9.
Step 1: Since X is a 5-digit number, the maximum sum of its digits (Y) would be 9*5 = 45 (if all digits were 9).
Step 2: Now, Y = 45. The sum of the digits of Y (Z) would be 4 + 5 = 9.
So, the maximum possible value of Z is 9.
Similar Questions
A number consists of two digits and the digit in the ten’s place exceeds that in the unit’s place by 5. if 5 times the sum of the digits be added from the numbers, the digits of the number are reversed. Then the sum of digits of the number is?
Given two integers s and d. The task is to find the smallest number such that the sum of its digits is s and the number of digits in the number are d. Return a string that is the smallest possible number. If it is not possible then return -1.
he sum of five distinct whole numbers is 337. If 60 is the smallest of them, what is the maximum value the largest number can have?Options :917097274
For a 4-digit number, the sum of its digits in the thousands, hundreds and tens places is 14, the sum of its digits in the hundreds, tens, and units places is 15, and the tens place digit is 4 more than the units place digit. Then the highest possible 4-digit number satisfying the above conditions is
The units digit of a two-digit number is one less than one-half the tens digit. The number with the digits interchanged is 5 more than thrice the sum of the digits. Find the original number.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.