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The point of tangency between an isocost line and an isoquant is necessarilyGroup of answer choicesthe profit-maximizing combination of inputs that should be hired to produce that output level.the least costly combination of inputs that can be hired to produce the output level.both the profit-maximizing and least costly combination of inputs that can be used to produce the output level.the minimum amount of output that can be attained for that level of expenditure.

Question

The point of tangency between an isocost line and an isoquant is necessarilyGroup of answer choicesthe profit-maximizing combination of inputs that should be hired to produce that output level.the least costly combination of inputs that can be hired to produce the output level.both the profit-maximizing and least costly combination of inputs that can be used to produce the output level.the minimum amount of output that can be attained for that level of expenditure.

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Solution

The point of tangency between an isocost line and an isoquant is necessarily the least costly combination of inputs that can be hired to produce the output level.

Here's why:

  1. An isoquant represents all combinations of inputs that yield the same level of output.

  2. An isocost line represents all combinations of inputs that can be purchased for a given total cost.

  3. The point where the isoquant and isocost line are tangent to each other represents the least costly combination of inputs that can be used to produce a certain level of output. This is because at this point, the firm is getting the most output for its money, i.e., it is minimizing its costs.

  4. This point does not necessarily represent the profit-maximizing combination of inputs, because profit maximization depends not only on costs but also on revenues.

  5. Similarly, this point does not represent the minimum amount of output that can be attained for that level of expenditure, because the isocost line represents all combinations of inputs that can be purchased for a given total cost, not the minimum output that can be achieved with that cost.

This problem has been solved

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