To find the common zeroes of the two polynomials, we first need to find the zeroes of each polynomial separately.

1. For the first polynomial x^3 + 5x^2 - 9x - 45 = 0, we can factor it to get (x-3)(x+3)(x+5) = 0. So the zeroes of the first polynomial are x = 3, -3, -5.

2. For the second polynomial x^3 + 8x^2 + 15x = 0, we can factor out an x to get x(x^2 + 8x + 15) = 0. Further factoring gives x(x+3)(x+5) = 0. So the zeroes of the second polynomial are x = 0, -3, -5.

3. Comparing the zeroes of the two polynomials, we see that the common zeroes are x = -3 and x = -5.

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To find the common zeroes of the two polynomials, we first need to find the zeroes of each polynomial separately.

1. For the first polynomial x^3 + 5x^2 - 9x - 45 = 0, we can factor it to get (x-3)(x+3)(x+5) = 0. So the zeroes of the first polynomial are x = 3, -3, -5.

2. For the second polynomial x^3 + 8x^2 + 15x = 0, we can factor out an x to get x(x^2 + 8x + 15) = 0. Further factoring gives x(x+3)(x+5) = 0. So the zeroes of the second polynomial are x = 0, -3, -5.

3. Comparing the zeroes of the two polynomials, we see that the common zeroes are x = -3 and x = -5.

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To find the common zeroes of the two polynomials, we first need to find the zeroes of each polynomial separately.

1. For the first polynomial x^3 + 5x^2 - 9x - 45 = 0, we can factor it to get (x-3)(x+3)(x+5) = 0. So the zeroes of the first polynomial are x = 3, -3, -5.

2. For the second polynomial x^3 + 8x^2 + 15x = 0, we can factor out an x to get x(x^2 + 8x + 15) = 0. Further factoring gives x(x+3)(x+5) = 0. So the zeroes of the second polynomial are x = 0, -3, -5.

3. Comparing the zeroes of the two polynomials, we see that the common zeroes are x = -3 and x = -5.

Find the common zeroes of the polynomial x3 + 5x2 – 9x – 45 and x3 + 8x2 + 15x.

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