The figures below are similar.6 mm4 mmV1 = ? V2 = 8 mm3What is the volume of the larger rectangular pyramid?V1 = cubic millimetresSubmit

The problem involves similar figures and their volumes. The volume of similar figures is related by the cube of the ratio of their corresponding sides.

Given that the figures are similar, the ratio of their corresponding sides is 4mm/6mm = 2/3.

The volume of the smaller pyramid (V1) is unknown, but the volume of the larger pyramid (V2) is given as 8 mm^3.

We can set up the equation as follows:

V1/V2 = (2/3)^3

We can solve for V1 by multiplying both sides by V2:

V1 = V2 * (2/3)^3

Substitute the given value of V2 into the equation:

V1 = 8 mm^3 * (2/3)^3

V1 = 8 mm^3 * (8/27)

V1 = 64/27 mm^3

So, the volume of the smaller pyramid is 64/27 cubic millimeters.