Select the correct answer.Edward is making a rectangular picture frame. He wants the perimeter of the frame to be no more than 96 inches. He also wants the length of the frame to be greater than or equal to the square of 4 inches less than its width.Create a system of inequalities to model the above situation and use it to determine how many of the solutions are viable. A. No part of the solution region is viable because the length or width cannot be negative. B. The entire solution region is viable. C. Part of the solution region includes a negative length; therefore, all solutions are not viable for the given situation. D. Part of the solution region includes a negative width; therefore, not all solutions are viable for the given situation.
Question
Select the correct answer.Edward is making a rectangular picture frame. He wants the perimeter of the frame to be no more than 96 inches. He also wants the length of the frame to be greater than or equal to the square of 4 inches less than its width.Create a system of inequalities to model the above situation and use it to determine how many of the solutions are viable. A. No part of the solution region is viable because the length or width cannot be negative. B. The entire solution region is viable. C. Part of the solution region includes a negative length; therefore, all solutions are not viable for the given situation. D. Part of the solution region includes a negative width; therefore, not all solutions are viable for the given situation.
Solution
Let's denote the length of the frame as L and the width as W.
From the problem, we have two inequalities:
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The perimeter of the frame is no more than 96 inches. The formula for the perimeter of a rectangle is P = 2L + 2W. So, we have 2L + 2W ≤ 96 or simplified to L + W ≤ 48.
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The length of the frame is greater than or equal to the square of 4 inches less than its width. So, we have L ≥ (W - 4)^2.
Now, we need to consider the physical constraints of the problem. Both L and W must be positive, because we can't have a negative length or width.
So, we have L > 0 and W > 0.
Combining all these inequalities, we have a system of inequalities:
- L + W ≤ 48
- L ≥ (W - 4)^2
- L > 0
- W > 0
Looking at these inequalities, we can see that part of the solution region includes a negative length (when W is less than 4, (W - 4)^2 is positive but L is negative), therefore, not all solutions are viable for the given situation.
So, the correct answer is C. Part of the solution region includes a negative length; therefore, all solutions are not viable for the given situation.
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