Use the chain rule to find the derivative of the following function.𝑓(𝑥)=4(𝑥3−2𝑥2+2𝑥)100𝑓′(𝑥)=
Question
Use the chain rule to find the derivative of the following function.𝑓(𝑥)=4(𝑥3−2𝑥2+2𝑥)100𝑓′(𝑥)=
Solution
Sure, here is the step by step solution:
The chain rule states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function.
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Identify the outer function and the inner function. In this case, the outer function is u^100 and the inner function is u = 4(x^3 - 2x^2 + 2x).
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Find the derivative of the outer function. The derivative of u^100 with respect to u is 100u^99.
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Find the derivative of the inner function. The derivative of 4(x^3 - 2x^2 + 2x) with respect to x is 12x^2 - 8x + 2.
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Apply the chain rule. The derivative of the original function is the product of the derivative of the outer function and the derivative of the inner function.
So, f'(x) = 100(4x^3 - 8x^2 + 2x)^99 * (12x^2 - 8x + 2).
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