A sequential circuit contains 3 D-Flip flops. How many states are present?
Question
A sequential circuit contains 3 D-Flip flops. How many states are present?
Solution
The number of states in a sequential circuit is determined by the number of flip-flops it contains. Each flip-flop can be in one of two states: 0 or 1.
So, for a sequential circuit with 3 D-Flip flops, the number of states is 2^n, where n is the number of flip-flops.
Step 1: Identify the number of flip-flops. In this case, n = 3.
Step 2: Use the formula 2^n to calculate the number of states.
So, the number of states is 2^3 = 8.
Therefore, a sequential circuit with 3 D-Flip flops has 8 states.
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