A builder discovers that a load of bricks is twice as heavy as a load of sticks. The total weight of 4 loads of bricks and 4 loads of sticks is 771 kilograms.What is the total weight of 1 load of bricks and 3 loads of sticks?
Question
A builder discovers that a load of bricks is twice as heavy as a load of sticks. The total weight of 4 loads of bricks and 4 loads of sticks is 771 kilograms.What is the total weight of 1 load of bricks and 3 loads of sticks?
Solution
Let's break this down:
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Let's denote the weight of a load of sticks as S and the weight of a load of bricks as B. From the problem, we know that B = 2S.
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We also know that 4B + 4S = 771 kg.
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We can substitute B = 2S into the second equation to get 4(2S) + 4S = 771 kg, which simplifies to 8S + 4S = 771 kg, or 12S = 771 kg.
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Solving for S, we find that S = 771 kg / 12 = 64.25 kg.
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Substituting S = 64.25 kg into B = 2S, we find that B = 2 * 64.25 kg = 128.5 kg.
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Finally, the total weight of 1 load of bricks and 3 loads of sticks is B + 3S = 128.5 kg + 3 * 64.25 kg = 321.25 kg.
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