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A builder discovers that a load of bricks is twice as heavy as a load of sticks. The total weight of 4 loads of bricks and 4 loads of sticks is 771 kilograms.What is the total weight of 1 load of bricks and 3 loads of sticks?

Question

A builder discovers that a load of bricks is twice as heavy as a load of sticks. The total weight of 4 loads of bricks and 4 loads of sticks is 771 kilograms.What is the total weight of 1 load of bricks and 3 loads of sticks?

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Solution

Let's break this down:

  1. Let's denote the weight of a load of sticks as S and the weight of a load of bricks as B. From the problem, we know that B = 2S.

  2. We also know that 4B + 4S = 771 kg.

  3. We can substitute B = 2S into the second equation to get 4(2S) + 4S = 771 kg, which simplifies to 8S + 4S = 771 kg, or 12S = 771 kg.

  4. Solving for S, we find that S = 771 kg / 12 = 64.25 kg.

  5. Substituting S = 64.25 kg into B = 2S, we find that B = 2 * 64.25 kg = 128.5 kg.

  6. Finally, the total weight of 1 load of bricks and 3 loads of sticks is B + 3S = 128.5 kg + 3 * 64.25 kg = 321.25 kg.

This problem has been solved

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