Here is a step-by-step guide on how to solve this problem in Python:

1. First, you need to define a function that will count the number of 1's in the binary representation of a number. You can use the built-in `bin` function to convert the number to binary, and then count the 1's using the `count` method.

```python
def count_ones(n):
return bin(n).count('1')
```

2. Next, you need to sort the array. Python's built-in `sorted` function can take a `key` argument, which is a function that will be used to determine the sort order. You can use the `count_ones` function as the key.

```python
arr = sorted(arr, key=count_ones)
```

3. However, this will only sort the numbers by the number of 1's in their binary representation. If two numbers have the same number of 1's, you need to sort them in ascending order. To do this, you can modify the `key` function to return a tuple. The `sorted` function will first sort by the first element of the tuple, and then by the second element.

```python
arr = sorted(arr, key=lambda x: (count_ones(x), x))
```

4. Finally, return the sorted array.

```python
return arr
```

Here is the complete code:

```python
def sortByBits(arr):
def count_ones(n):
return bin(n).count('1')

arr = sorted(arr, key=lambda x: (count_ones(x), x))
return arr
```

This function will sort the array in ascending order by the number of 1's in the binary representation of each number, and in case of a tie, it will sort the numbers in ascending order.

Question

Here is a step-by-step guide on how to solve this problem in Python:

1. First, you need to define a function that will count the number of 1's in the binary representation of a number. You can use the built-in `bin` function to convert the number to binary, and then count the 1's using the `count` method.

```python
def count_ones(n):
    return bin(n).count('1')
```

2. Next, you need to sort the array. Python's built-in `sorted` function can take a `key` argument, which is a function that will be used to determine the sort order. You can use the `count_ones` function as the key.

```python
arr = sorted(arr, key=count_ones)
```

3. However, this will only sort the numbers by the number of 1's in their binary representation. If two numbers have the same number of 1's, you need to sort them in ascending order. To do this, you can modify the `key` function to return a tuple. The `sorted` function will first sort by the first element of the tuple, and then by the second element.

```python
arr = sorted(arr, key=lambda x: (count_ones(x), x))
```

4. Finally, return the sorted array.

```python
return arr
```

Here is the complete code:

```python
def sortByBits(arr):
    def count_ones(n):
        return bin(n).count('1')

arr = sorted(arr, key=lambda x: (count_ones(x), x))
    return arr
```

This function will sort the array in ascending order by the number of 1's in the binary representation of each number, and in case of a tie, it will sort the numbers in ascending order.

Knowee AI · Accepted Answer