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Consider the queues Q1 containing four elements and Q2 containing none (shown as the Initial State in the figure). The only operations allowed on these two queues are Enqueue (Q, element) and Dequeue (Q). The minimum number of Enqueue operations on Q1 required to place the elements of Q1 in Q2 in reverse order (shown as the Final State in the figure) without using any additional storage is ______________.*2 points4568

Question

Consider the queues Q1 containing four elements and Q2 containing none (shown as the Initial State in the figure). The only operations allowed on these two queues are Enqueue (Q, element) and Dequeue (Q). The minimum number of Enqueue operations on Q1 required to place the elements of Q1 in Q2 in reverse order (shown as the Final State in the figure) without using any additional storage is ______________.*2 points4568

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Solution

The question seems to be incomplete as there is no figure provided for reference. However, based on the information given, if you want to reverse the order of elements in Q1 and place them in Q2 using only Enqueue and Dequeue operations, you would need to perform 4 Enqueue operations.

Here's the step-by-step process:

  1. Dequeue an element from Q1 and Enqueue it into Q2. Repeat this step until Q1 is empty. Now, Q2 contains the elements of Q1 but in the same order, not reversed.

  2. To reverse the order, Dequeue an element from Q2 and Enqueue it back into Q1. Repeat this step until Q2 is empty. Now, Q1 contains its original elements but in reversed order.

  3. Finally, Dequeue an element from Q1 and Enqueue it into Q2. Repeat this step until Q1 is empty. Now, Q2 contains the elements of Q1 in reversed order.

So, you need to perform 4 Enqueue operations on Q1 to achieve the final state.

This problem has been solved

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