How to desgin the address format?• We need, block number, word/Byte number, cache line numberblock no. Offset(word/Byte id )• The CPU gives out a 32-bit address Addr. Each byte has an address.• The block size is b, one block b bytes.• Then Addr is in Block Addr/b, and it is the (Addr%b)-th byte in the block.• Modulo is a math operation that finds the remainder, mod, or symbol %.• If the divisor (block size) is in the form of b = 2n, then— A%b is given by the rightmost n-bits of A,— A/b is given by the remaining bits.8 / 28*byte-addressable

Which format specifier returns the memory address and in which form?

Which format specifier returns the memory address and in which form?Options%p, hexadecimal%p, octadecimal%lf, hexadecimal%lf, octadecimal

Consider a machine with a byte addressable main memory of 216 bytes and block size of 8bytes.Assume that a direct mapped cache consisting of 32 lines is used with this machine.• How is a 16-bit memory address divided into tag, line number, and byte number?• Into what line would bytes with each of the following addresses be stored?000100010001101111000011001101001101000000011101• Suppose the byte with address 0001101000011010 is stored in the cache. Whatare the addresses of the other bytes stored along with it?• How many total bytes of memory can be stored in the cache?

Every address generated by the CPU is divided into two parts. They are ____________A.frame offset & page offsetB.page number & page offsetC.page offset & frame bitD.frame bit & page number

A digital computer space has a memory unit of 64k x 16 and a cache memory of 1k words. How manybits are there in the tag of the address format?*810166