Which of the following will loop until the user enters a value for String for str2 that does NOT match str1? (Mark ALL that apply)Scanner input = new Scanner(System.in);String str1 = input.nextLine();String str2 = input.nextLine();while ( CONDITION ) { str2 = input.nextLine();}Group of answer choicesstr1.equals(str2)str2.equals(str1)str2 == str1str1 == str2
Question
Which of the following will loop until the user enters a value for String for str2 that does NOT match str1? (Mark ALL that apply)Scanner input = new Scanner(System.in);String str1 = input.nextLine();String str2 = input.nextLine();while ( CONDITION ) { str2 = input.nextLine();}Group of answer choicesstr1.equals(str2)str2.equals(str1)str2 == str1str1 == str2
Solution
The correct conditions that will make the loop continue until the user enters a value for str2 that does NOT match str1 are:
- str1.equals(str2)
- str2.equals(str1)
The conditions str2 == str1 and str1 == str2 are not correct because in Java, using '==' to compare strings can lead to unexpected results. This is because '==' checks if the two strings are the same object, not if they are equal in value.
Similar Questions
Fill the below code to compare two strings and print "yes" if they are same else print "no".Don't consider the case. Example, if the strings are "Good" and "good" the output should be "yes".Code : Scanner sc=new Scanner(System.in); String s1=sc.next(); String s2=sc.next(); if() System.out.println("yes"); else System.out.println("no");
Select the correct answerThe while loop repeats a set of code while the condition is not met?OptionsTrueFalse
Develop a Java program with a method for comparing two strings.
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Given the following lines of code, which of the following is the result of a user entering ABCDEFG when prompted?String stringValue = input.nextLine();char singleChar = stringValue.charAt(0);System.out.println(singleChar);a.)Bb.)Errorc.)Ad.)0
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